围栏
分析
见《进阶指南》第314
页。
实现
#include <iostream>
#include <queue>
#include <algorithm>
using namespace std;
const int N = 16010, M = 110;
struct node {
int l, p, s;
bool operator < (const node& o) const {
return s < o.s;
}
};
int n, m;
node a[M];
deque<int> dq;
int f[M][N];
int main () {
cin >> n >> m;
for (int i = 1; i <= m; ++ i) cin >> a[i].l >> a[i].p >> a[i].s;
sort(a + 1, a + m + 1);
for (int i = 1; i <= m; ++ i) {
for (int j = 0; j <= n; ++ j) {
f[i][j] = f[i - 1][j];
if (j >= 1) f[i][j] = max(f[i][j], f[i][j - 1]);
int l = a[i].l, p = a[i].p, s = a[i].s;
if (!dq.empty() && dq.front() < j - l) dq.pop_front();
if (j >= s && !dq.empty()) {
int k = dq.front();
f[i][j] = max(f[i][j], f[i - 1][k] + (j - k) * p);
}
if (j < s) {
while (!dq.empty()
&& f[i - 1][dq.back()] - dq.back() * p <= f[i - 1][j] - j * p
) {
dq.pop_back();
}
dq.push_back(j);
}
}
}
cout << f[m][n] << endl;
return 0;
}