泥泞的区域
分析
见《进阶指南》第434
页。
实现
#include <iostream>
#include <cstring>
using namespace std;
const int N = 52, M = 2510;
struct edge {
int to, next;
};
edge e[2 * M];
int idx, head[M];
int n, m;
char a[N][N];
int b[N][N][2];
int ln, rn;
bool mark[M];
int match[M];
void add_edge (int u, int v) {
e[idx].to = v;
e[idx].next = head[u];
head[u] = idx ++;
}
bool dfs (int cur) {
for (int i = head[cur]; i != -1; i = e[i].next) {
int to = e[i].to;
if (mark[to] == true) continue;
mark[to] = true;
if (match[to] == 0 || dfs(match[to]) == true) {
match[to] = cur;
return true;
}
}
return false;
}
int main () {
memset(head, -1, sizeof(head));
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++ i)
scanf("%s", a[i] + 1);
ln = rn = 1;
for (int i = 1; i <= n; ++ i) { // 行泥泞块
for (int j = 1; j <= m + 1; ++ j) { // m + 1
if (a[i][j] == '*')
b[i][j][0] = ln;
else
++ ln;
}
}
-- ln;
for (int j = 1; j <= m; ++ j) { // 列泥泞块
for (int i = 1; i <= n + 1; ++ i) {
if (a[i][j] == '*')
b[i][j][1] = rn;
else
++ rn;
}
}
-- rn;
for (int i = 1; i <= n; ++ i) {
for (int j = 1; j <= m; ++ j) {
if (a[i][j] == '*') {
add_edge(b[i][j][0], ln + b[i][j][1]);
add_edge(ln + b[i][j][1], b[i][j][0]);
}
}
}
int res = 0;
for (int i = 1; i <= ln; ++ i) {
memset(mark, 0, sizeof(mark));
if (dfs(i) == true) ++ res;
}
printf("%d", res);
return 0;
}