道路与航线
分析
见《进阶指南》第357
页。
实现
#include <iostream>
#include <cstring>
#include <queue>
using namespace std;
const int N = 25010, M = 150010;
struct edge {
int to, next, w;
};
edge e[M];
int idx, head[N], in_deg[N];
struct node {
int idx, dis;
bool operator < (const node& o) const {
return dis > o.dis;
}
};
int n, r, p, s;
int tot, c[N];
int dis[N];
bool mark[N];
void add_edge (int u, int v, int w) {
e[idx].w = w;
e[idx].to = v;
e[idx].next = head[u];
head[u] = idx ++;
}
void dfs (int cur) {
for (int i = head[cur]; i != -1; i = e[i].next) {
int to = e[i].to;
if (c[to] == 0) {
c[to] = tot;
dfs(to);
}
}
}
void topo_sort () {
memset(dis, 0x3f, sizeof(dis));
dis[s] = 0;
queue<int> q;
for (int i = 1; i <= tot; ++ i)
if (in_deg[i] == 0)
q.push(i);
while (!q.empty()) {
int cur = q.front();
q.pop();
priority_queue<node> pq;
for (int i = 1; i <= n; ++ i)
if (c[i] == cur)
pq.push({ i, dis[i] });
while (!pq.empty()) {
int cur = pq.top().idx;
pq.pop();
if (mark[cur] == true) continue;
mark[cur] = true;
for (int i = head[cur]; i != -1; i = e[i].next) {
int to = e[i].to, w = e[i].w;
if (dis[cur] + w < dis[to]) {
dis[to] = dis[cur] + w;
if (c[to] == c[cur])
pq.push({ to, dis[to] });
}
if (c[to] != c[cur] && (-- in_deg[c[to]] == 0))
q.push(c[to]);
}
}
}
}
int main () {
memset(head, -1, sizeof(head));
cin >> n >> r >> p >> s;
for (int i = 1, u, v, w; i <= r; ++ i) {
cin >> u >> v >> w;
add_edge(u, v, w);
add_edge(v, u, w);
}
for (int i = 1; i <= n; ++ i) {
if (c[i] == 0) {
c[i] = ++ tot;
dfs(i);
}
}
for (int i = 1, u, v, w; i <= p; ++ i) {
cin >> u >> v >> w;
add_edge(u, v, w);
++ in_deg[c[v]];
}
topo_sort();
for (int i = 1; i <= n; ++ i) {
if (dis[i] > 1e9) { // 负权边
cout << "NO PATH" << endl;
} else {
cout << dis[i] << endl;
}
}
return 0;
}