Hamilton
路径
最短分析
见《进阶指南》第7
页。
实现
#include <iostream>
#include <cstring>
using namespace std;
const int N = 20;
int n, dis[N][N];
int f[N][1 << N];
int main () {
cin >> n;
for (int i = 0; i < n; ++ i)
for (int j = 0; j < n; ++ j)
cin >> dis[i][j];
memset(f, 0x3f, sizeof(f));
f[0][1] = 0;
for (int k = 1; k <= (1 << n); ++ k)
for (int i = 0; i < n; ++ i)
if ((k >> i) & 1)
for (int j = 0; j < n; ++ j)
if ((k >> j) & 1)
f[i][k] = min(f[i][k], f[j][k ^ (1 << i)] + dis[j][i]);
cout << f[n - 1][(1 << n) - 1] << endl;
return 0;
}