巡逻
分析
见《进阶指南》第371
页。
实现
#include <iostream>
#include <cstring>
#include <queue>
#define inf 0x3f3f3f3f
using namespace std;
const int N = 100010;
struct edge {
int to, next, w;
};
edge e[2 * N];
int idx, head[N];
int n, k, L2 = -inf;
int dis[N], eid[N];
void add_edge (int u, int v, int w) {
e[idx].w = w;
e[idx].to = v;
e[idx].next = head[u];
head[u] = idx ++;
}
int bfs (int rt) {
memset(dis, 0x3f, sizeof(dis));
queue<int> q;
dis[rt] = 0;
q.push(rt);
while (!q.empty()) {
int cur = q.front();
q.pop();
for (int i = head[cur]; i != -1; i = e[i].next) {
int to = e[i].to, w = e[i].w;
if (dis[to] == inf) {
dis[to] = dis[cur] + w;
eid[to] = i;
q.push(to);
}
}
}
int ver = 1;
for (int i = 2; i <= n; ++ i)
if (dis[i] > dis[ver])
ver = i;
return ver;
}
void dfs (int cur, int fa) {
for (int i = head[cur]; i != -1; i = e[i].next) {
int to = e[i].to, w = e[i].w;
if (to == fa) continue;
dfs(to, cur);
L2 = max(L2, dis[cur] + dis[to] + w);
dis[cur] = max(dis[cur], dis[to] + w);
}
}
void modify (int x, int y) {
while (y != x) {
e[eid[y]].w = -1;
e[eid[y] ^ 1].w = -1;
y = e[eid[y] ^ 1].to;
}
}
int main () {
memset(head, -1, sizeof(head));
scanf("%d%d", &n, &k);
for (int i = 1, u, v; i <= n - 1; ++ i) {
scanf("%d%d", &u, &v);
add_edge(u, v, 1);
add_edge(v, u, 1);
}
int x = bfs(1);
int y = bfs(x);
int res = 2 * (n - 1) - dis[y] + 1;
if (k == 1) {
printf("%d", res);
} else {
modify(x, y);
memset(dis, 0, sizeof(dis));
dfs(1, -1);
printf("%d", res - L2 + 1);
}
return 0;
}